Final answer:
To calculate the deformation for a 5-kN tensile load applied to a 1.6-mm flat steel plate, we can use Hooke's Law. First, calculate the stress using the formula stress = Force/Area.
Then calculate the strain using the formula strain = stress/E. Finally, use the formula deformation = strain * length to calculate the deformation.
Step-by-step explanation:
To calculate the deformation for a 5-kN tensile load applied to a 1.6-mm flat steel plate, we can use Hooke's Law. Hooke's Law states that the deformation is directly proportional to the applied force and inversely proportional to the material's stiffness.
First, we need to calculate the stress using the formula: stress = Force/Area. Given that the force is 5 kN and the area is 1.6 mm * the thickness of the plate, we can calculate the stress.
Then, using the formula: strain = stress/E, where E is the Young's modulus of the material, we can calculate the strain. Finally, we can use the formula: deformation = strain * length, where length is the initial length of the plate, to calculate the deformation.
The question relates to calculating the deformation of a flat steel plate when a tensile load is applied, according to Hooke's Law for shearing stress and strain.
To find the deformation, also known as elongation, we first need to calculate the tensile stress (σ) using the formula σ = F/A, where F is the force applied and A is the cross-sectional area of the plate. Assuming the plate width is much larger than its thickness, A = width × thickness.
Once the stress is determined, we can use Hooke's Law for tensile deformation, which is ε = σ/E, where ε is the strain and E is the Young's modulus of the material. The deformation (ΔL) can then be found using ΔL = ε × L0, where L0 is the original length of the plate.