Question

If pressure is 101.325 kPa, temperature is 300 K, and there are 2 moles of gas, what is the volume of the gas?

Options:
a) 50.6625 L
b) 100.0 L
c) 150.9938 L
d) 200.0 L

Answer 1

To find the volume of the gas given the pressure, temperature, and number of moles, we use the ideal gas law. By first calculating the ideal gas constant (R) under STP conditions, we then substitute the student's conditions into the ideal gas equation to determine the volume, finding that the volume is approximately 50.6625 L, which corresponds to option a).

Step-by-step explanation:

To find the volume of the gas, we will use the ideal gas law, which is PV = nRT, where P is pressure, V is volume, n is the number of moles of the gas, R is the ideal gas constant, and T is the temperature. First, we need to calculate the value of R using the given conditions at STP: 101.325 kPa of pressure, 22.414 L of volume, and 273.15 K for temperature.

Substituting these values into the ideal gas equation gives us:
R = PV / nT = (101.325 kPa)(22.414 L) / (1 mol)(273.15 K)
Thus, we can find R in kPa·L/(mol·K).

Now, we apply the ideal gas law with the provided data for the student's question. With 2 moles of gas at 101.325 kPa and 300 K, we can solve for V:

V = (nRT) / P = (2 mol)(R)(300 K) / (101.325 kPa)

Using the previously calculated R, we can find the volume:

V ≈ 50.6625 L

Therefore, the answer is option a) 50.6625 L.