Final answer:
To find the real power absorbed by each impedance in parallel, one would calculate the power factor for each impedance and apply the formula P = V²/R × cos θ. However, without additional information such as source voltage or total current, the distribution of the total power to individual impedances cannot be determined from the provided information alone.
Step-by-step explanation:
To determine the real power absorbed by each impedance when two impedances Z1=3+j4 ohm and Z2=10 ohm are connected in parallel, and the total real power delivered is 1100 W, we use the concept of power dissipation in resistive components of the impedances.
The power factor for each impedance can be found using the resistive part of the impedance and its magnitude. For Z1, we have a resistive component R1 = 3 ohms and a magnitude |Z1| = √(3² + 4²) = 5 ohms. The power factor for Z1 is cos θ1 = R1 / |Z1| = 3/5.
For Z2, since it is purely resistive, the power factor is cos θ2 = 1. The real power absorbed by any component is P = V²/R × cos θ. To find the voltage across the impedances, we need to use the total power formula, P_total = V² * (1/R_eq) where R_eq is the equivalent resistance of the parallel combination.
However, since we do not have the source voltage in the problem provided, direct calculation of individual powers using only the given total power and resistances cannot be performed. Typically, additional information like the source voltage or the total current would be necessary to distribute the total power across individual impedances precisely.