Final answer:
There are 3.26 moles of NH3 in 55.5 g of NH3, which is closest to option (c) 3.00 moles, although the exact value is not listed as an option.
Step-by-step explanation:
The question seeks to determine the moles of NH3 in 55.5 g of NH3. The molar mass of ammonia (NH3) can be calculated by adding the atomic masses of nitrogen (N) and hydrogen (H): 14.01 g/mol for nitrogen and 1.01 g/mol for each hydrogen. Ammonia has one nitrogen atom and three hydrogen atoms, so its molar mass is 14.01 g/mol + (3 × 1.01 g/mol) = 17.04 g/mol.
To find the moles of ammonia, we divide the mass of the sample by its molar mass: 55.5 g NH3 ÷ 17.04 g/mol = 3.26 mol. Hence, 3.26 moles of NH3 are present in 55.5 g of NH3. This value does not perfectly match any of the options provided, but the closest option would be 3.00 moles (c). If we are strictly looking for the closest option among a), b), c), and d), we would choose (c) 3.00 moles.
Please note that the options provided may have been intended for a slightly different question or there might be a typo, as the actual calculated number of moles doesn’t exactly match the available choices. In a real examination scenario, it would be advisable to report this discrepancy to the examiner.