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Let tsx, yd - x² / ln(x + 1)y.

Evaluate ts³, 1d.
a) ts³, 1d = 1
b) ts³, 1d = 2
c) ts³, 1d = 3
d) ts³, 1d = 4

User Core Xii
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1 Answer

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Final answer:

The evaluation of ts³, 1d, where ts(x, y) = x² / ln(x + 1)y, results in a value of approximately 6.49 after substituting x = 3 and y = 1 and simplifying. None of the provided multiple-choice options match this result.

Step-by-step explanation:

The student's question pertains to evaluating a function ts(x, y) - x² / ln(x + 1)y at a specific point (3, 1) to find ts³, 1d. This requires substituting the values x = 3 and y = 1 into the given function and simplifying accordingly

  1. Identify the given function: ts(x, y) = x² / ln(x + 1)y.
  2. Substitute x = 3 and y = 1 into the function, resulting in ts³, 1d = 3² / ln(3 + 1).¹
  3. Simplify the expression: ts³, 1d = 9 / ln(4).
  4. Calculate the natural logarithm of 4: ln(4) is approximately 1.3863.
  5. Divide 9 by the value of ln(4): ts³, 1d = 9 / 1.3863.
  6. Complete the division to find the value of ts³, 1d, which is approximately 6.49.

Therefore, none of the provided options (a) 1, (b) 2, (c) 3, (d) 4 match the correct evaluation of ts³, 1d. The answer appears to be approximately 6.49, which is not one of the listed choices, suggesting a possible error in the problem statement or options provided.

User AnupamBhusari
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8.4k points
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