Final answer:
The standard deviation of the Gaussian distribution given by the function f(x) = e^(-ax²) is 1/√a.
Step-by-step explanation:
The standard deviation of the Gaussian distribution given by the function f(x) = e^(-ax²) is 1/√a.
To find the standard deviation, we can equate it to the square root of the variance. The variance of a continuous probability distribution is given by the formula o² = Σ (x − µ)² P(x), where x represents the values, µ is the mean, and P(x) represents the corresponding probability. For the Gaussian distribution, we have f(x) = e^(-ax²), and the mean µ is zero since the curve is symmetrical.
Therefore, the variance o² is given by:
o² = ∫ (x - 0)² e^(-ax²) dx
Using integration techniques, we can solve this integral to find the variance. Then, taking the square root of the variance gives us the standard deviation:
o = √(o²)
Hence, the standard deviation is 1/√a.