214k views
1 vote
The centers of an 11.0 kg lead ball and a 110 g lead ball are separated by 11.0 cm. Calculate the gravitational force between the two lead balls. Include the gravitational force formula and provide the numerical result.

User VVN
by
8.0k points

1 Answer

3 votes

Final answer:

The gravitational force between an 11.0 kg and a 110 g lead ball separated by 11.0 cm is approximately 6.0 × 10⁻ N, calculated using Newton's Law of Universal Gravitation.

Step-by-step explanation:

To calculate the gravitational force between two lead balls, we use Newton's Law of Universal Gravitation, which states that the gravitational force (F) between two masses (m1 and m2) is directly proportional to the product of their masses and inversely proportional to the square of the distance (r) between their centers. The formula is given as F = G * (m1 * m2) / r^2, where G is the universal gravitational constant, 6.674 × 10⁻¹¹ N·m²/kg². For the two lead balls with masses of 11.0 kg and 110 g (0.11 kg), and separated by a distance of 11.0 cm (0.11 m), the gravitational force is calculated as follows:

F = (6.674 × 10⁻¹¹ N·m²/kg²) * ((11.0 kg) * (0.11 kg)) / (0.11 m)²

This calculation yields a gravitational force of approximately 6.0 × 10⁻ N.

User Neverov
by
8.3k points