Question

A solution of HCl with a volume of 25 mL is titrated to the endpoint with 0.250M NaOH. If it takes 34.56 mL of NaOH to reach the endpoint, calculate the concentration of the HCl solution.

Answer 1

The concentration of the HCl solution is 0.3456 M.

Step-by-step explanation:

In this titration, HCl is being titrated with NaOH to the endpoint. The balanced chemical equation for the reaction is:

HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)

From the given information, we know that 34.56 mL of the 0.250 M NaOH solution is required to reach the endpoint. Using this information, we can calculate the number of moles of NaOH used in the reaction:

Number of moles of NaOH = volume of NaOH (L) × concentration of NaOH (M)

Number of moles of NaOH = 0.03456 L × 0.250 M = 0.00864 mol NaOH

Since the reaction is 1:1 between HCl and NaOH, the number of moles of HCl is also 0.00864 mol.

Next, we can calculate the concentration of the HCl solution:

Concentration of HCl = number of moles of HCl / volume of HCl (L)

Concentration of HCl = 0.00864 mol / 0.025 L = 0.3456 M