Final answer:
The electric dipole created by charges of −4.70nC and +4.70nC separated by 3.20 mm has a dipole moment magnitude of 15.04nC·mm and is directed from the negative charge to the positive charge.
Step-by-step explanation:
An electric dipole is a pair of equal and opposite point charges separated by a distance. In the scenario described, point charges q1=−4.70nC and q2=4.70nC are separated by 3.20 mm, creating a dipole.
The dipole moment, denoted as p, is given by the product of one of the charges and the separation distance (p=qd). Thus, the electric dipole will have a magnitude of p=|q1|×d=4.70nC×03.20mm=15.04nC·mm.
The direction of the dipole moment vector is defined from the negative charge to the positive charge.