Final answer:
The zeros of the function f(x) = 2x³ - x² - 8x + 4 are -2, -1, and 1/2.
Step-by-step explanation:
Quadratic Equation
The zeros of the function are the values of x for which the function equals zero. To find the zeros of the function f(x) = 2x³ - x² - 8x + 4, we set f(x) equal to zero and solve for x.
2x³ - x² - 8x + 4 = 0
Using synthetic division or factoring, we find that the zeros of the function are x = -2, x = -1, and x = 1/2.