Question

To stretch an ideal spring 8.00 cm from its unstretched length, 19.0 J of work must be done. What is the force constant of this spring? Express your answer with the appropriate units.

Answer 1

The force constant of the spring is 5,937.5 N/m.

Step-by-step explanation:

The force constant of a spring can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement or stretch of the spring from its equilibrium position. In this case, we are given that the spring stretches 8.00 cm from its unstretched length and 19.0 J of work is done. The formula for calculating the force constant is:

k = (2 * work) / (stretch^2)

Substituting the given values, we have:

k = (2 * 19.0 J) / (0.08 m)^2

Simplifying the equation, we find that the force constant of the spring is 5,937.5 N/m.