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Determine [H₃O⁺] of a 0.160 M solution of formic acid (Ka = 1.8×10⁻⁴).

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Final answer:

The hydronium ion concentration in a 0.160 M solution of formic acid is determined by calculating the square root of the product of the dissociation constant, Ka, and the formic acid concentration, assuming x is much less than the initial concentration of the acid.

Step-by-step explanation:

To determine the concentration of hydronium ions ([H3O+]) in a 0.160 M solution of formic acid with a known Ka of 1.8×10−4, we use the equilibrium expression for the dissociation of a weak acid:

HA ⇌ H+ + A−

Ka = [H+][A−]/[HA]

Since [H+] and [A−] are equal and the acid dissociates slightly, we can simplify the Ka expression:

Ka = x2 / (0.160 − x)

Assuming x << 0.160, we can approximate it as follows:

Ka ≈ x2 / 0.160

Solving for x (which is equal to [H3O+]), we get:

x = √(Ka × 0.160) = √(1.8×10−4 × 0.160)

After calculation, the x value is found and represents the concentration of H3O+.

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