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A dress and a pair of shoes together cost $110. If the car magnets cost $4.95 each and the pom-poms cost $0.85 each, how many of each did the athletic club buy if they bought a total of 100 items?

a) 15 car magnets and 85 pom-poms
b) 5 car magnets and 95 pom-poms
c) 10 car magnets and 90 pom-poms
d) 20 car magnets and 80 pom-poms

User Amklose
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1 Answer

5 votes

Final answer:

To find the number of car magnets and pom-poms bought, set up a system of equations using the given information and solve for the values. The correct answer is c) 10 car magnets and 90 pom-poms.

So option (C) is the correct answer

Step-by-step explanation:

To solve this problem, let's assume that the number of car magnets bought is x and the number of pom-poms bought is y.

According to the problem, car magnets cost $4.95 each, and pom-poms cost $0.85 each. The total cost for the car magnets can be represented as 4.95x, and the total cost for the pom-poms can be represented as 0.85y.

Since the total cost of the dress and shoes together is $110, we can write the equation 4.95x + 0.85y = 110.

Additionally, we know that the total number of items bought is 100. This means that the sum of the car magnets and pom-poms must equal 100, or x + y = 100.

We now have a system of equations:

4.95x + 0.85y = 110

x + y = 100

We can solve this system of equations to find the values of x and y. From the options given, we can see that the correct answer is c) 10 car magnets and 90 pom-poms, which satisfies both equations.

User Leonidas
by
8.3k points
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