Question

A sample of a gas (5.0 mol) at 1.0 atm is expanded at constant temperature from 10.0 L to 15.0 L. The final pressure is ___ atm.

a) 0.67 atm
b) 1.5 atm
c) 2.0 atm
d) 5.0 atm

Answer 1

Using Boyle's Law, which states that pressure and volume are inversely proportional at a constant temperature, the final pressure after expanding a gas from 10.0 L to 15.0 L at a constant temperature is calculated as 0.67 atm.

Step-by-step explanation:

The question is asking for the final pressure of a gas after it has expanded at a constant temperature.

According to Boyle's Law, which states that the pressure of a given mass of an ideal gas is inversely proportional to its volume when the temperature stays constant (P1V1 = P2V2), we can calculate the final pressure after the expansion.

Here's how to calculate it:

• Initial pressure (P1) = 1.0 atm
• Initial volume (V1) = 10.0 L
• Final volume (V2) = 15.0 L

We are looking to find the final pressure (P2). Using the formula from Boyle's Law, we get:

P1V1 = P2V2

1.0 atm * 10.0 L = P2 * 15.0 L

P2 = (1.0 atm * 10.0 L) / 15.0 L = 0.67 atm

The final pressure is 0.67 atm.