Final answer:
The pressure of the gas inside the apparatus, assuming atmospheric pressure is 760 mmHg and H₂ is 50 mm, would be 760 mmHg minus 50 mmHg, which equals 710 mmHg. None of the options provided match this answer, suggesting there may be a typo or error in the question.
Step-by-step explanation:
The pressure of the gas inside the apparatus is determined by considering the atmospheric pressure and the height of mercury H₂. Given that atmospheric pressure is 760 mmHg and H₂ is 50 mm, if the mercury level on the side open to the atmosphere is higher, it means that the gas pressure is lower than the atmospheric pressure by the height of H₂. Therefore, the pressure of the gas is atmospheric pressure minus H₂, which is:
760 mmHg - 50 mmHg = 710 mmHg.
This is not one of the provided options, and thus the question might contain a typo or an error in the choices provided. However, usually, the answer would be calculated as above when given the atmospheric pressure and the height of mercury in a manometer. To provide a correct answer, the correct values or choices need to be verified.
The pressure of the gas inside the apparatus can be determined by adding the height of the mercury column H₂ to the atmospheric pressure. Assuming H₂ is 50 mm and atmospheric pressure is 760 mmHg, the pressure of the gas would be 760 mmHg + 50 mmHg = 810 mmHg. So, the correct answer would be 810 mmHg.