Question

How many atoms of carbon are present in

3.78 moles of carbon tetrafluoride, CF₄?

a) 2.28×10²4 atoms of carbon
b) 1.52×10 ²4 atoms of carbon
c) 3.78×10²4 atoms of carbon
d) 6.02×10²4 atoms of carbon

Answer 1

In 3.78 moles of carbon tetrafluoride, CF₄, there are 2.28×10²´ atoms of carbon. This is calculated by multiplying the number of moles by Avogadro's number which is 6.022 × 10²³ atoms per mole.

Step-by-step explanation:

Calculating Atoms of Carbon in Carbon Tetrafluoride (CF₄)

To determine how many atoms of carbon are present in 3.78 moles of carbon tetrafluoride, CF₄, we can use Avogadro's number, which is 6.022 × 10²³ atoms per mole. Since there is one atom of carbon in each molecule of CF₄, the number of carbon atoms will be equal to the number of CF₄ molecules.

The calculation is as follows:

1. 
   
3. 
   
5. 
   

Therefore, the correct answer is (a) 2.28×10²´ atoms of carbon.