Final answer:
The percent (w/v) concentration of a solution containing 100 meq of ammonium chloride per liter is 53.5%.
Step-by-step explanation:
The percent (w/v) concentration of a solution can be calculated by dividing the mass of the solute by the volume of the solution and multiplying by 100.
In this case, we have:
Mass of ammonium chloride = 100 meq = 100 * 53.5 mg (since 1 mole of ammonium chloride is equal to its molecular weight in grams)
Volume of solution = 1 L
Concentration (w/v) = (mass of solute / volume of solution) * 100 = (100 * 53.5 mg / 1 L) * 100 = 5350 mg/L
Converting mg/L to percent gives us: 5350 mg/L * (1 g / 1000 mg) * (100 / 1 L) = 53.5 g/L
Therefore, the percent (w/v) concentration of the solution is 53.5%.