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What is the percent (w/v) concentration of a solution containing 100 meq of ammonium chloride (mw = 53.5) per liter?

a) 1.87%
b) 3.74%
c) 5.61%
d) 7.48%

1 Answer

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Final answer:

The percent (w/v) concentration of a solution containing 100 meq of ammonium chloride per liter is 53.5%.

Step-by-step explanation:

The percent (w/v) concentration of a solution can be calculated by dividing the mass of the solute by the volume of the solution and multiplying by 100.

In this case, we have:

Mass of ammonium chloride = 100 meq = 100 * 53.5 mg (since 1 mole of ammonium chloride is equal to its molecular weight in grams)

Volume of solution = 1 L

Concentration (w/v) = (mass of solute / volume of solution) * 100 = (100 * 53.5 mg / 1 L) * 100 = 5350 mg/L

Converting mg/L to percent gives us: 5350 mg/L * (1 g / 1000 mg) * (100 / 1 L) = 53.5 g/L

Therefore, the percent (w/v) concentration of the solution is 53.5%.

User Sergey Podgornyy
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