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The bar has a cross-sectional area of 400(10^-6) m. If it is subjected to a triangular axial distributed loading along its length which is 0 at x = 0 and 9 kN/mat x = 1.5 m, and to two concentrated loads as shown, determine the average normal stress in the bar as a function of x for 0 lessthanorequalto x < 0.6 m.

User MatDobek
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Final answer:

Determining the average normal stress in a bar under a distributed load requires integrating the load distribution along the bar's length and dividing by the cross-sectional area.

Step-by-step explanation:

The average normal stress in a bar due to a distributed load can be found by integrating the load distribution over the length of the bar and then dividing by the cross-sectional area. In this scenario, there is a triangular axial distributed loading, which involves a varying force applied longitudinally along the bar. Our focus is to find the average normal stress as a function of x for the given range.

However, due to the complexity and missing details, like the positions of the concentrated loads or the entire load distribution function, the precise answer in 200 words format is not feasible here. Generally, to find the stress at a point x in the bar under distributed loads, we use the formula

σ = (F/A) where

The force F would be determined by integrating the distributed load from x = 0 to the point of interest.

User Zainul Abideen
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