Question

For each of the following compounds, circle all stereocenters. If there are no stereocenters in the compound, circle "no stereocenters."

a) CH₃CHClBr
b) H₂C=CH-CH₂-CHO
c) C₆H₁2O₆
d) C₄H₁0

Answer 1

The compounds in (a), (c), and (d) do not have any stereocenters. The compound in (b) has one stereocenter.

Step-by-step explanation:

For each of the following compounds, circle any stereocenters. If there are no stereocenters, circle 'no stereocenters'.

a) CH₃CHClBr - This compound does not have any stereocenters because all of the carbon atoms are bonded to the same groups.

b) H₂C=CH-CH₂-CHO - This compound has one stereocenter, which is the carbon atom in the middle bonded to four different groups.

c) C₆H₁₂O₆ - This compound does not have any stereocenters because all of the carbon atoms are bonded to the same groups.

d) C₄H₁₀ - This compound does not have any stereocenters because all of the carbon atoms are bonded to the same groups.