Question

Assume the machine is to be implemented using flip-flops with synchronous reset whose setup time is 0.5ns and propagation delay from clock to...

a) 1.0ns
b) 1.5ns
c) 2.0ns
d) 2.5ns

Answer 1

To charge a capacitor with a 10-mA current and a charge of 5.0 mC, it would take 0.50 s.

Step-by-step explanation:

The question is asking how long it would take a 10-mA current to charge a capacitor with 5.0 mC. To solve this, we can use the formula:

Charge (C) = Current (A) × Time (s)

Given that the current is 10 mA (which is 0.01 A) and the charge is 5.0 mC (which is 0.005 C), we can rearrange the formula to solve for time:

Time (s) = Charge (C) ÷ Current (A)

Plugging in the values, we get:

Time (s) = 0.005 C ÷ 0.01 A = 0.5 s

Therefore, the correct answer is a) 0.50 s.