Final answer:
The maximum mass of NH₃ that can be produced by the reaction of N₂ with H₂ is 34.06 g.
Step-by-step explanation:
The balanced equation for the reaction between N₂ and H₂ to produce NH₃ is:
N₂ (g) + 3H₂ (g) → 2NH₃ (g)
To find the maximum mass of NH₃ that can be produced, we need to determine the limiting reactant. The limiting reactant is the reactant that is completely consumed and determines the maximum amount of product that can be formed. To do this, we need to compare the number of moles of N₂ and H₂. Let's assume we have 1 mole of N₂. According to the balanced equation, 3 moles of H₂ are needed to react with 1 mole of N₂. So, the maximum amount of NH₃ that can be produced is 2 moles.
Now, we can calculate the molar mass of NH₃:
Molar mass of NH₃ = 14.01 g/mol + 1.01 g/mol x 3 = 17.03 g/mol
Finally, we can calculate the maximum mass of NH₃ using the molar mass and the number of moles:
Maximum mass of NH₃ = 17.03 g/mol x 2 mol = 34.06 g
Therefore, the correct answer is d. 34.06 g.