Final answer:
The determinant of a real 2x2 matrix with two complex eigenvalues must be a real number because the eigenvalues come in complex conjugate pairs and their product is a sum of squares of real numbers.
Step-by-step explanation:
When dealing with a real 2x2 matrix b that has two complex eigenvalues, one can say that the determinant of b must be a real number. This can be shown using the fact that the complex eigenvalues of a matrix come in complex conjugate pairs.
If the two complex eigenvalues are a + ib and a - ib, where a and b are real numbers, the determinant of matrix b is the product of its eigenvalues, which would be (a + ib) multiplied by (a - ib), resulting in a2 + b2. Since both aa and b are real numbers, the determinant is also a real number.
Therefore, the correct answer is (a) It must be a real number.
When a real 2x2 matrix has two complex eigenvalues, the determinant of the matrix can be either real or imaginary.
Let's say the eigenvalues of matrix b are a+bi and a-bi, where a and b are real numbers.
The determinant of matrix b is given by (a+bi)*(a-bi) = a^2 - (bi)^2 = a^2 + b^2.
Since a^2 and b^2 are both real numbers, the determinant of matrix b can either be a real number or 0 (if a=b=0).