Final answer:
The given system of equations has 1 solution.
Step-by-step explanation:
The given system of equations is:
Y = 2x^2 - 18x + 45
y = 2x - 5
To determine the number of solutions, we need to find the points of intersection between the two equations. We can do this by setting the two equations equal to each other:
2x^2 - 18x + 45 = 2x - 5
Simplifying the equation, we get:
2x^2 - 20x + 50 = 0
This is a quadratic equation. We can use the discriminant to determine the number of solutions. The discriminant is given by:
Discriminant = b^2 - 4ac
In this case, a = 2, b = -20, and c = 50. Plugging in the values, we get:
Discriminant = (-20)^2 - 4(2)(50)
Discriminant = 400 - 400
Discriminant = 0
Since the discriminant is zero, the quadratic equation has 1 solution. Therefore, the given system of equations has 1 solution.