Question

How many moles of Ni3 contain 2.55×10^24 iodine atoms?

A) 0.85 moles
B) 1.70 moles
C) 2.55 moles
D) 3.40 moles

Answer 1

To find the number of moles of Ni3 that contain 2.55×1024 iodine atoms, divide the number of atoms by three to get the number of molecules, and then divide by Avogadro's number to convert to moles. The closest answer is 1.70 moles.

Step-by-step explanation:

The question asks us to determine how many moles of Ni3 would contain 2.55×1024 iodine atoms. Since each molecule of Ni3 contains three iodine atoms, we first need to divide the total number of iodine atoms by three to find out how many molecules of Ni3 there are:

2.55×1024 iodine atoms ÷ 3 = 8.5×1023 molecules of Ni3

Next, we use Avogadro's number, which is approximately 6.022×1023 atoms per mole, to convert the number of molecules to moles:
8.5×1023 molecules ÷ 6.022×1023 molecules/mol = 1.41 moles (to two decimal places)

Thus, the closest answer from the given options is B) 1.70 moles.