Final answer:
The net ionic equation for the reaction between cadmium acetate and manganese(II) bromide is Cd2+(aq) + 2 Br-(aq) → CdBr2(s). The acetate and manganese ions are spectator ions and are not included in this net ionic equation.
Step-by-step explanation:
The question at hand involves writing the net ionic equation for the reaction between cadmium acetate and manganese(II) bromide. First, it's important to understand that the net ionic equation only includes the ions and molecules directly involved in the reaction, leaving out the spectator ions.
Cadmium acetate is written as Cd(OAc)2 with OAc representing the acetate ion (CH3COO-). Manganese(II) bromide is MnBr2. When these two compounds react, the cadmium and manganese ions swap their associated anions, forming cadmium bromide and manganese acetate.
The complete ionic equation before removing the spectator ions is:
- Cd2+(aq) + 2 OAc-(aq) + Mn2+(aq) + 2 Br-(aq) → CdBr2(s) + Mn2+(aq) + 2 OAc-(aq)
Since the acetate ions and manganese ions appear on both the reactant and product sides of the equation, they are spectator ions and are not included in the net ionic equation. The net ionic equation is simply:
Cd2+(aq) + 2 Br-(aq) → CdBr2(s)