Final answer:
No precipitate forms when solutions of lead(II) nitrate and sodium acetate are mixed because both potential products, lead(II) acetate and sodium nitrate, are soluble in water.
Step-by-step explanation:
When aqueous solutions of lead(II) nitrate and sodium acetate are mixed, we must consider the potential formation of new compounds through a double-replacement reaction. According to solubility rules, most nitrates are soluble in water, which means that sodium nitrate will remain in solution. However, considering the other possible product, lead(II) acetate, and referring to the solubility rules, we find that lead acetate is also soluble in water (though with some exceptions for high concentrations).
Therefore, when solutions of lead(II) nitrate (Pb(NO3)2) and sodium acetate (CH3COONa) are mixed, both of the possible new compounds, lead(II) acetate and sodium nitrate, remain in the aqueous phase and no precipitate is formed. This is because lead(II) acetate is soluble in water. As a result, the solution will contain Pb2+, CH3COO-, Na+, and NO3- ions, all in the aqueous state. Thus, the correct answer should be none of the provided options since no precipitate forms under these conditions.