Final answer:
The ion 197/79 Au³ has 79 protons, 118 neutrons, and 76 electrons, making Option A the correct choice.
Step-by-step explanation:
The ion described in the question is Au³ with a mass number of 197 and an atomic number of 79. To find the number of protons, electrons, and neutrons, we look at the atomic number, mass number, and the charge of the ion.
- Thus, the correct answer to how many protons, neutrons, and electrons are in the ion 197/79 Au³ is Option A: Protons: 79, Neutrons: 118, Electrons: 76.