147k views
5 votes
An object is swinging in a horizontal circle on a length of string that is 0.93 m long. Its centripetal acceleration is 26.36 m/s^2. What is the time it takes the object to complete one horizontal circle?

a) 2 seconds
b) 3 seconds
c) 4 seconds
d) 5 seconds

User Qualaelay
by
7.6k points

1 Answer

3 votes

Final answer:

The time for an object to complete one revolution in a horizontal circle can be found with the formula for centripetal acceleration, velocity, and the circumference of the circle. Using the given acceleration and string length, the actual time calculated for one revolution is approximately 1.18 seconds, which does not match any of the provided answer choices.

Step-by-step explanation:

To find the time it takes for an object swinging in a horizontal circle to complete one revolution, we need to use the formula for centripetal acceleration ac = v2/r, where ac is the centripetal acceleration, v is the linear velocity, and r is the radius of the circle. We can rearrange this formula to solve for the velocity: v = √(ac × r). With the given centripetal acceleration of 26.36 m/s2 and a string length of 0.93 m, which is the radius, the velocity can be calculated as v = √(26.36 m/s2 × 0.93 m).

Once we have the velocity, we can find the circumference of the circle (which is one complete revolution) using C = 2πr. The time for one revolution, T, can then be found by dividing the circumference by the velocity (T = C/v). The actual calculations yield v = √(24.5148 m2/s2) = 4.951 m/s and the circumference C = 2π×0.93 m ≈ 5.846 m, resulting in the time T = 5.846 m / 4.951 m/s ≈ 1.18 seconds, which is none of the provided options. It's important to note that the actual time does not match any of the options given, indicating a possible error in the question or the provided answer choices.

User Francois Bourgeois
by
7.9k points