Question

A student fires a cannonball diagonally with a speed of 32 m/s from a height of 54 m as shown. Determine all unknowns.

A) Time of flight, Range, Maximum height
B) Initial velocity, Launch angle, Time of flight
C) Horizontal velocity, Vertical velocity, Maximum height
D) Acceleration due to gravity, Launch angle, Range

Answer 1

To solve this problem, we can use the equations of projectile motion to find the time of flight, range, and maximum height of the cannonball.

Step-by-step explanation:

To solve this problem, we can use the equations of projectile motion. First, let's find the time of flight.

Using the equation for vertical displacement h = v02sin2(θ)/2g, where h is the initial height, v0 is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity, we can plug in the given values: h = 54 m, v0 = 32 m/s, and g = 9.8 m/s2.

Next, we can use the equation for range R = v02sin(2θ)/g to find the range. Plugging in the given values: v0 = 32 m/s and g = 9.8 m/s2.

Finally, let's find the maximum height. The maximum height can be found using the equation for vertical displacement h = (v0sin(θ))2/2g. Plugging in the given values: v0 = 32 m/s, and g = 9.8 m/s2.