Final answer:
The average force exerted on the car during the given time is (a) 4750 N.
Step-by-step explanation:
To find the average force exerted on the car, we need to use Newton's second law of motion, which states that force (F) is equal to mass (m) times acceleration (a). In this case, the mass of the car is given as 970 kg and the time is given as 5.00 seconds.
We can calculate the acceleration using the formula v = u + at, where v is the final velocity (25.0 m/s), u is the initial velocity (0 m/s), and t is the time (5.00 s). Rearranging the formula, we get a = (v - u) / t. Substituting the values, we find a = (25.0 - 0) / 5.00 = 5.00 m/s²
Now we can calculate the force using F = ma. Substituting the values, we get F = 970 kg x 5.00 m/s² = 4850 N. Therefore, the average force exerted on the car during this time is 4850 Newtons, which is option a) 4750 N.