Question

If 832 joules of energy are required to raise the temperature of a sample of aluminum from 20.0 °C to 97.0 °C, and the specific heat of aluminum is 0.90 J/(g °C), what is the mass of the aluminum?

a) 80 g
b) 100 g
c) 120 g
d) 140 g

Answer 1

The correct answer is (c) 120 g.

Step-by-step explanation:

To calculate the mass of the aluminum, we can use the formula:

Q = mcΔT

Where Q is the energy required, m is the mass, c is the specific heat, and ΔT is the change in temperature.

Plugging in the given values:

832 J = m * 0.90 J/(g °C) * (97.0 °C - 20.0 °C)

Simplifying the equation, we get:

m = 832 J / (0.90 J/(g °C) * 77.0 °C) = 120 g

Therefore, the mass of the aluminum is 120 g. So, the correct answer is (c) 120 g.