Final answer:
The molarity of a 14.79% m/v solution of propylene glycol is calculated to be 1.94 M, by dividing the number of moles (0.194) by the volume of solution in liters (0.1 L). However, this calculated value does not match any of the provided options.
Step-by-step explanation:
To calculate the molarity of a 14.79% m/v propylene glycol solution, we first need the definition of m/v percent concentration, which is the mass of the solute per volume of solution. Here, it means that we have 14.79 grams of propylene glycol for every 100 mL of solution.
We then use the molar mass (mm) of propylene glycol, which is 76.09 g/mol, to find the number of moles in 14.79 grams:
Moles of propylene glycol = mass (in grams) / molar mass (in g/mol)
Moles of propylene glycol = 14.79 g / 76.09 g/mol = 0.194 moles
Since molarity (M) is moles of solute per liter of solution, we need to convert the volume from milliliters to liters:
100 mL = 0.1 L
Thus, the molarity (M) is:
Molarity = moles / volume (L)
Molarity = 0.194 moles / 0.1 L = 1.94 M
However, none of the provided answer options match this calculated value. Thus, there may be an error in the question or in the given answer choices. In a real-world scenario, it would be prudent to revisit the calculations or clarify the question.