Question

Calculate the change in energy (in kJ) for the reaction shown below, if you begin with 52 grams of fluorine (F2), and the ΔHrxn = -542 kJ.

a. -27984 kJ
b. -5224 kJ
c. -10.46 kJ
d. -10460 kJ

Answer 1

The change in energy for the reaction is -742.54 kJ.

Step-by-step explanation:

The enthalpy change for the reaction can be calculated using the equation Q = m * ΔH, where Q is the change in energy, m is the mass of the substance, and ΔH is the enthalpy change. In this case, we have 52 grams of fluorine (F2) and ΔHrxn = -542 kJ. To calculate the change in energy, we first need to convert the mass of fluorine to moles using the molar mass of fluorine.

1. Calculate the moles of fluorine: moles = mass / molar mass = 52g / 38.0g/mol = 1.37 mol
2. Use the equation Q = m * ΔH to calculate the change in energy: Q = 1.37 mol * -542 kJ/mol = -742.54 kJ

Therefore, the change in energy for the reaction is -742.54 kJ.