Final answer:
To find the pH of a 5.2x10^-8 M KOH solution, calculate the pOH first by taking the negative logarithm of the OH- concentration and then subtract that value from 14 to obtain the pH.
Step-by-step explanation:
To calculate the pH of a 5.2x10-8 M solution of KOH(aq) at 25 °C, we first need to recognize that KOH is a strong base and will completely dissociate in water. The concentration of OH- in the solution will be equal to the concentration of KOH, which is 5.2x10-8 M. Next, we calculate the pOH by taking the negative logarithm of the OH- concentration:
pOH = -log(5.2x10-8)
After calculating the pOH, we use the relationship pH + pOH = 14 at 25 °C to find the pH:
pH = 14 - pOH
Substituting the calculated pOH value will give us the pH of the solution.