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What is the value used for t for the 51st term of the arithmetic sequence: 29, 9, -11, ...?

User Chris Yin
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Final answer:

The value used for t for the 51st term of the arithmetic sequence is -971.

Step-by-step explanation:

The arithmetic sequence given is 29, 9, -11, ...

To find the value used for t for the 51st term, we notice that the common difference between the terms is -20. This is because each term is obtained by subtracting 20 from the previous term. So, we can use the formula:

tn = a + (n-1)d

where tn is the nth term, a is the first term, n is the term number, and d is the common difference.

Plugging in the values, we get:

t51 = 29 + (51-1)(-20) = 29 + 50(-20) = -971

Therefore, the value used for t for the 51st term of the arithmetic sequence is -971.

User Stewenson
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