Final answer:
To find the probability of getting at least 15 left-handed people in a randomly selected group of 100 people, we can use the binomial distribution formula. The probability of getting exactly k left-handed people in a group of n randomly selected people is given by: P(X = k) = C(n, k) * p^k * (1 - p)^(n-k). Using a binomial probability calculator, the probability of getting at least 15 left-handed people in a group of 100 people is approximately 0.2544.The correct option is b.
Step-by-step explanation:
To find the probability of getting at least 15 left-handed people in a randomly selected group of 100 people, we can use the binomial distribution formula. The probability of getting exactly k left-handed people in a group of n randomly selected people is given by:
P(X = k) = C(n, k) * p^k * (1 - p)^(n-k)
where C(n, k) is the number of combinations of n items taken k at a time, p is the probability of an individual being left-handed (0.10), and n is the size of the group (100).
To find the probability of getting at least 15 left-handed people, we need to sum up the probabilities of getting 15, 16, 17, ..., up to 100 left-handed people. We can do this using the binompdf function on a calculator or statistical software.Using a binomial probability calculator, the probability of getting at least 15 left-handed people in a group of 100 people is approximately 0.2544.The correct option is b.