Final answer:
The helicopter has component velocities of approximately 77.8 km/h horizontally (vx) and 54.3 km/h vertically (vy), when traveling at 95 km/h at a 35-degree angle to the ground.
Step-by-step explanation:
To find the component velocities of a helicopter traveling at 95 km/h at an angle of 35 degrees to the ground, you will need to use trigonometric functions. Specifically, you'll use the cosine function to find the horizontal component (vx) and the sine function to find the vertical component (vy).
The horizontal velocity can be calculated using the following formula:
vx = v * cos(\theta)
So, for the helicopter:
vx = 95 km/h * cos(35 degrees)
vx ≈ 77.8 km/h
Similarly, the vertical velocity is given by:
vy = v * sin(\theta)
vy = 95 km/h * sin(35 degrees)
vy ≈ 54.3 km/h
Therefore, the helicopter's horizontal (vx) and vertical (vy) component velocities are approximately 77.8 km/h and 54.3 km/h, respectively.