Question

What is the balanced form of the chemical equation shown below?

C6H12O6(s) + O2(g) → H2O(l) + CO2(g)
Option 1: C6H12O6(s) + 6O2(g) → 6H2O(l) + 6CO2(g)
Option 2: C6H12O6(s) + 2O2(g) → 2H2O(l) + 2CO2(g)
Option 3: C6H12O6(s) + 3O2(g) → 3H2O(l) + 3CO2(g)
Option 4: C6H12O6(s) + 4O2(g) → 4H2O(l) + 4CO2(g)

Answer 1

Option 1: C6H12O6(s) + 6O2(g) → 6H2O(l) + 6CO2(g) is the correct balanced form of the chemical equation for the reaction of glucose with oxygen because it contains the same number of carbon, hydrogen, and oxygen atoms on both the reactant and product sides of the equation.

Step-by-step explanation:

To determine which of the given options represents the balanced chemical equation for the reaction of glucose (C6H12O6) with oxygen (O2), we need to ensure that the number of atoms of each element on the reactant side is equal to the number of atoms of that element on the product side.

Looking at Option 1: C6H12O6(s) + 6O2(g) → 6H2O(l) + 6CO2(g), we can verify the balance:

• Carbon: There are 6 C on both sides.
• Hydrogen: There are 12 H atoms on both sides (6 molecules of H2O).
• Oxygen: There are 6 O atoms from C6H12O6 plus 6 × 2 = 12 O atoms from 6 O2, making a total of 18 O atoms on the reactant side. These match the 12 O from 6 CO2 plus 6 O from 6 H2O, totally 18 O on the product side.

Therefore, Option 1 is the correct balanced form of the chemical equation.