Question

When we mix the solutions of lead (II) nitrate and potassium iodide.

(i) What is the colour of the precipitate formed? Can you name the compound precipitated?
(ii) Write the balanced chemical equation for this reaction.
(iii) Is this also a double displacement reaction?

Answer 1

When solutions of lead (II) nitrate and potassium iodide are mixed, a yellow precipitate of solid lead (II) iodide is formed, and the balanced chemical equation for this reaction is Pb(NO3)2(aq) + 2KI(aq) → 2KNO3(aq) + PbI2(s). This is a double displacement reaction.

Step-by-step explanation:

When solutions of lead (II) nitrate and potassium iodide are mixed, a yellow precipitate of solid lead (II) iodide is formed. The compound precipitated is lead (II) iodide.

The balanced chemical equation for this reaction is: Pb(NO3)2(aq) + 2KI(aq) → 2KNO3(aq) + PbI2(s)

Yes, this is a double displacement reaction because the cations (Pb2+ and K+) and the anions (NO3- and I-) in the reactants switch places to form new compounds.