The given inequality is "7/2 > b + 9/5". To solve for b, subtract 9/5 from both sides, resulting in "17/10 > b".
The inequality is 7/2 > b + 9/5. To solve for b, subtract 9/5 from both sides:
(7/2) - (9/5) > b
To combine the fractions, find a common denominator, which is 10. Multiply the first fraction by 5/5 and the second fraction by 2/2:
(35/10) - (18/10) > b
Now, subtract the numerators:
17/10 > b
So, the range of values for b that satisfies the inequality is b < 17/10 or b belongs to the open interval (-∞, 17/10).
Complete question:
What is the range of values for the variable b that satisfy the inequality 7/2 > b + 9/5?