1. Midpoints:
(a) The midpoint of (5,11) and (3,1) is (4,6).
(b) The midpoint of (7,-5) and (3,3) is (5,-1).
2. Missing Measures:
(a) FG = 2y + 18.
(b) FG = 8x - 30.
(c) FG = 42, a = 4.71.
**1. Find the coordinates of the midpoint:**
(a) For the points (5,11) and (3,1):
![\[ \text{Midpoint} = \left(\frac{{x_1 + x_2}}{2}, \frac{{y_1 + y_2}}{2}\right) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/ym8sm9kjy28c6lg3x95p63xwve5nk60lif.png)
![\[ \text{Midpoint} = \left(\frac{{5 + 3}}{2}, \frac{{11 + 1}}{2}\right) = (4, 6) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/kptaubupeagx0cpznn2u01io4n9x2uugzg.png)
(b) For the points (7,-5) and (3,3):
![\[ \text{Midpoint} = \left(\frac{{x_1 + x_2}}{2}, \frac{{y_1 + y_2}}{2}\right) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/ym8sm9kjy28c6lg3x95p63xwve5nk60lif.png)
![\[ \text{Midpoint} = \left(\frac{{7 + 3}}{2}, \frac{{-5 + 3}}{2}\right) = (5, -1) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/y921yahymss8qxmbnxcl7uwbu9hdh5b00g.png)
**2. Suppose M is the midpoint of FG. Find each missing measure:**
(a) For FM = 5y + 13, MG = 5 - 3y, and FG = ?
FG = FM + MG
FG = (5y + 13) + (5 - 3y)
FG = 2y + 18
(b) For FM = 3x - 4, MG = 5x - 26, and FG = ?
FG = FM + MG
FG = (3x - 4) + (5x - 26)
FG = 8x - 30
(c) For FM = 8a + 1, FG = 42, and a = ?
FG = FM + MG
42 = (8a + 1) + (8 - a)
42 = 7a + 9
7a = 33
a = 4.71 (rounded to two decimal places)