Question

Determine the total power of radiation emitted by the Moon if its cool night side has a

temperature TC = −153◦C and its hot day side has a temperature of TH = 107◦C. Assume
e = 1. The radius of the Moon 1,737 km. (Note: σ = 5.67 × 10−8 W/m2·K4).
a. 2.5 × 1012 W
b. 2.5 × 1014 W
c. 2.5 × 1016 W
d. 2.5 × 1018 W

Answer 1

The answer is the option "c. 2.5 x 1016 W"

Step-by-step explanation:

Formula: P = σ * A * e * T^4

TC ​= −153C + 273.15 = 120.15K

TH = 107C + 273.15 = 380.15K

Moon(A) - A = 4πr^2

Moon (r) is 1,737 km = 1,737,000 m

A = 4π * (1,737,000)^2

PC ​= σ *A * e * TC^4

PH​ = σ * A * e * TH^4

Ptotal​ = PC ​+ PH​

Approximately 2.5×1016W

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