The values of x₁ and x₂ are 2 and 1,000, respectively. The sum of x₁ and x₂ is: x₁ + x₂ = 2 + 1,000 = 1,002
To find the sum of x₁ and x₂, we need to solve the system of equations:
y = x² ...(1)
y = 1,002x - 2,000 ...(2)
Since both equations are equal to y, we can set them equal to each other:
x² = 1,002x - 2,000
To solve this quadratic equation, we can rearrange it into standard form:
x² - 1,002x + 2,000 = 0
Now, we can factorize the equation:
(x - 2)(x - 1,000) = 0
Setting each factor equal to zero, we get two solutions:
x - 2 = 0 => x = 2
x - 1,000 = 0 => x = 1,000
Therefore, the values of x₁ and x₂ are 2 and 1,000, respectively.
Therefore, the values of x₁ and x₂ are 2 and 1,000, respectively.The sum of x₁ and x₂ is:
Therefore, the values of x₁ and x₂ are 2 and 1,000, respectively.The sum of x₁ and x₂ is:x₁ + x₂ = 2 + 1,000 = 1,002
Complete question:
Y = x²
y = 1,002x - 2,000
If (x1,y1) and (x2,y2) are distinct solutions to the system of equations shown, what is the sum of x1 and x2?