Question

A sample of a gas (1.50 mol) is contained in a 15.0 L cylinder. The temperature is increased from 100°C to 150°C. The ratio of final pressure to initial pressure [ p2 p1 ] is

A) 1.15
B) 1.50
C) 1.85
D) 2.20

Answer 1

The ratio of the final pressure to the initial pressure of a gas sample is approximately 1.15.

Step-by-step explanation:

To solve this problem, we can use the ideal gas law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

First, we need to convert the temperatures from Celsius to Kelvin. The initial temperature is 100°C + 273.15 = 373.15 K, and the final temperature is 150°C + 273.15 = 423.15 K.

Next, let's use the ideal gas law to find the initial pressure: P1 = (n1 * R * T1) / V1 = (1.50 mol * 0.0821 atm/mol·K * 373.15 K) / 15.0 L = 10.03 atm.

Similarly, we can find the final pressure: P2 = (n1 * R * T2) / V1 = (1.50 mol * 0.0821 atm/mol·K * 423.15 K) / 15.0 L = 11.38 atm.

The ratio of the final pressure to the initial pressure is therefore: P2 / P1 = 11.38 atm / 10.03 atm = 1.13, which is approximately equal to option B) 1.15.