Final Answer:
The correct value for the given surface integral is 4e^2. Option D is answer.
Step-by-step explanation:
The surface integral involves the vector field with components 4xyi, 6x^2j, and 4yzk over the surface defined by z=xe^y.
The outward unit normal vector to the surface is given by the components ⟨e^y, -xe^y, 1⟩.
Calculate the magnitude of the normal vector: √(1 + x^2e^(2y)).
Evaluate the dot product of the vector field and the normal vector, and set up the integral.
Evaluate the double integral over the region defined by the projection of the surface onto the xy-plane.
The result is 4e^2, confirming option D.