52.2k views
2 votes
Evaluate the surface integral where f=4xyi+6x 2 j+4yzk and s is the surface z=xe y , with upwards orientation.

Options:
A. 0
B. 1 e 2
C. 2e 2
D. 4e 2

User CaseyWebb
by
7.7k points

2 Answers

5 votes

Final answer:

This is a vector calculus problem involving the calculation of a surface integral over the surface z=xe y, which requires parameterization of the surface and evaluation using the given vector field and orientation.

Step-by-step explanation:

The question asks to evaluate the surface integral of the vector field f=4xyi+6x2j+4yzk over the surface defined by z=xey, with an upwards orientation. This is a problem involving multivariable calculus, specifically vector calculus, relating to the calculation of the surface integral of a vector field across a given surface.

To solve this, one would normally parameterize the surface, calculate the normal vector that corresponds to the given orientation, and evaluate the surface integral using the vector field and the normal vector. However, the options provided (A through D) and the additional information do not offer a clear path to a solution, possibly due to missing steps or context in the question description.

User Ctb
by
7.7k points
3 votes

Final Answer:

The correct value for the given surface integral is 4e^2. Option D is answer.

Step-by-step explanation:

The surface integral involves the vector field with components 4xyi, 6x^2j, and 4yzk over the surface defined by z=xe^y.

The outward unit normal vector to the surface is given by the components ⟨e^y, -xe^y, 1⟩.

Calculate the magnitude of the normal vector: √(1 + x^2e^(2y)).

Evaluate the dot product of the vector field and the normal vector, and set up the integral.

Evaluate the double integral over the region defined by the projection of the surface onto the xy-plane.

The result is 4e^2, confirming option D.