Question

The value of x in Fe(NH₄)₂(SO₄)₂ * xH₂O can be found by determining the amount in mol of sulfate in the compound. A 0.982 g sample was dissolved in water, and extra water was added.

A. x=0.012 mol
B. x=0.021 mol
C. x=0.031 mol
D. x=0.041 mol

Answer 1

Without additional data, it's impossible to accurately determine the value of x for the hydrate Fe(NH4)2(SO4)2 · xH2O based on the information provided within the 0.982 g sample.

Step-by-step explanation:

To determine the value of x in the compound Fe(NH4)2(SO4)2 · xH2O, we need to find out how many moles of sulfate ions are present in the 0.982 g sample. Understanding that each formula unit of Fe(NH4)2(SO4)2 contains two moles of sulfate ions, we can establish a stoichiometric relationship between the mass of the sample and the moles of sulfate.

However, since the question does not provide enough data about the mass or moles of sulfate present to calculate x, we are unable to solve this problem directly. Additional information, such as the mass of the anhydrous sample or the mass of the precipitate formed after removal of the water of crystallization, would be necessary to answer this question.