Question

A 6.10 kg block is pushed 9.25m up a smooth 37° inclined plane by a horizontal force of 75N. If the initial speed of the block is 3.25 m/s up the plane calculate the initial kinetic energy of the block.

Answer 1

The initial kinetic energy of the block is 32.35625 Joules.

Step-by-step explanation:

The initial kinetic energy of the block can be calculated using the formula:

Kinetic Energy = 1/2 * mass * velocity^2

Given:

• Mass of the block (m) = 6.10 kg
• Initial speed of the block (v) = 3.25 m/s up the plane

Plugging in the values, we get:

Kinetic Energy = 1/2 * 6.10 kg * (3.25 m/s)^2

Simplifying the equation gives us:

Kinetic Energy = 1/2 * 6.10 kg * 10.5625 m^2/s^2

Kinetic Energy = 32.35625 J

Therefore, the initial kinetic energy of the block is 32.35625 Joules.