Question

A mixture containing only Al₂O₃ (FM101.96) and Fe₂O₃ (FM 159.69) weighs 2.019g.When heated under a stream of H₂,Al₂O₃ is unchanged, but Fe₂O₃ is converted to metallic Fe plus H₂O(g). If the residue weighs 1.774g, what isthe weight % of Fe₂O₃ in the originalmixture?

Answer 1

To find the weight % of Fe2O3 in the original mixture, subtract the weight of the residue from the initial weight of the mixture. Then, calculate the weight % using the formula: (weight of Fe2O3 / weight of original mixture) x 100%

Step-by-step explanation:

To find the weight % of Fe2O3 in the original mixture, we first need to find the weight of Fe2O3 in the mixture. We are given that the residue weighs 1.774g. From the given information, we know that the weight of the Fe2O3 is the difference between the initial weight of the mixture (2.019g) and the weight of the residue (1.774g). So, the weight of the Fe2O3 in the original mixture is 2.019g - 1.774g = 0.245g.

To calculate the weight % of Fe2O3, we use the formula: (weight of Fe2O3 / weight of original mixture) x 100%. Substituting the values, we get: (0.245g / 2.019g) x 100% = 12.12%.

Therefore, the weight % of Fe2O3 in the original mixture is 12.12%.