Final answer:
The z-score for a sample mean of 80, with a population mean of 75 and a standard deviation of 15, for a sample size of nine, is 1.0, which corresponds to option A.
Step-by-step explanation:
The z-score of the sample mean is a measure of how many standard deviations the sample mean is from the population mean. Since the population has a mean (μ) of 75 and a standard deviation (σ) of 15, and the sample mean (\( \bar{x} \)) is 80, we can use the formula:
Z = (\( \bar{x} \) - μ) / (σ/√n)
where n is the sample size. For this sample size of 9:
Z = (80 - 75) / (15/√9)
Z = 5 / (15/3)
Z = 5 / 5
Z = 1.0