Question

It takes a student time t to push a block of mass m at a constant velocity over a distance d. The coefficient of friction is represented by the symbol f. How much power in watts was applied to the block by the student?

a. mgdfriction/delta T
b. mgtfriction/delta T
c. mgd/delta T
d. mgt/delta T

Answer 1

The power applied to the block by the student can be calculated using the formula P = Fv, where P is power, F is force, and v is velocity.

Step-by-step explanation:

The power applied to the block by the student can be calculated using the formula P = Fv, where P is power, F is force, and v is velocity.

In this case, the force applied by the student is equal to the force of friction, which can be calculated using the equation Ff = μmg, where Ff is the force of friction, μ is the coefficient of friction, m is the mass of the block, and g is the acceleration due to gravity.

Since the block is pushed at a constant velocity, the force of friction is equal to the force applied by the student. Therefore, the power applied to the block can be calculated as P = Ff * v = μmgv.

Substituting the options into the equation, we find that the correct expression for the power applied to the block is d. mgt/deltaT.

In this case, the force applied by the student is equal to the force of friction, which can be calculated using the equation Ff = μmg, where Ff is the force of friction, μ is the coefficient of friction, m is the mass of the block, and g is the acceleration due to gravity.

Since the block is pushed at a constant velocity, the force of friction is equal to the force applied by the student. Therefore, the power applied to the block can be calculated as P = Ff * v = μmgv.